Wednesday, December 12, 2012
If a head was round , the circumference C would equal 2*pi*r. So the radius of the head would equal C/(2*pi).
The circumference of a padded helm with .75" of padding CH should equal 2*pi* (r+.75). Replacing the r with the formula above gives CH=2*pi* (C/(2*pi)+.75). Simplify to CH=C+(2*pi*.75) Again for our 23" head this gives a helm circumference of 27.71" or an additional 4.71 inches of circumference to allow for padding. Round it up to 5.
To put it another way, multiply the amount of padding to be added by 2pi or 6.28 to get the amount to add to the helm circumference.
Friday, November 2, 2012
Thursday, October 11, 2012
Well, it has been over a month since my last post, but Open Shop keeps happening every week. Here are a few highlights:
Monday, September 3, 2012
The 2012 Hammer-In sponsored by the North Texas Blacksmith Association ran from noon Friday Aug. 31 to noon Monday Sept. 3rd. I arrived Friday evening and had a full weekend of learning, playing with metal, and meeting some of the colorful characters of the armouring world. Friday evening got off to a great start as I met the one-and-only Ugo Serrano. I looked at the repouse' tools that he uses and the ones brought by Mykaru. Then, working with Jim Sotelo (Ameliano) I cut up 2 foil blades, a broken epee, and two 3' lengths of piano wire (pre-hardened 1060 rod in 3/16" and 1.4") into tool-length bits. Some of these bits I turned into repousse' and chasing tools.